Startintentsenderforresult Deprecated Android

Code snippet: private fun requestHint() { val hintRequest = HintRequest.Builder() .setPhoneNumberIdentifierSupported(true) .build() val credentialsClient =

Solution 1:

Use the below code -

privatefunshowPhoneNumberSuggestion() {

    val hintRequest = HintRequest.Builder()
        .setPhoneNumberIdentifierSupported(true)
        .build()

    val options = CredentialsOptions.Builder()
        .forceEnableSaveDialog()
        .build()

    // Then pass the hint request object to// credentialsClient.getHintPickerIntent()// to get an intent to prompt the user to// choose a phone number.val credentialClient = Credentials.getClient(applicationContext, options)
    val intent = credentialClient.getHintPickerIntent(hintRequest)
    try {

        val intentSenderRequest = IntentSenderRequest.Builder(intent.intentSender).build()
        phonePickIntentResultLauncher.launch(intentSenderRequest)

    } catch (e: IntentSender.SendIntentException) {
        e.printStackTrace()
    }
}

For ActivityResult, use -

privateval phonePickIntentResultLauncher =
    registerForActivityResult(ActivityResultContracts.StartIntentSenderForResult()) { result ->
        if (result != null) {
            val intent = result.dataval credential = intent?.getParcelableExtra<Credential>(Credential.EXTRA_KEY)
            binding.inputPhone.setText(credential?.id)
        }
    }

Remember there are no request codes.

Use different result launchers for every particular task.